26 Jan The Algebra of International Law
26.01.08
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5 + 10 = X
X – Y = 0 if
Y = 1, 2, 3, 4, or 5
5 + 10 = X
X – Z = X/192 if
Z = 6, 7, 8, 9, 10, 11, 12, 13, 14, or 15
What is X, Y, and Z where Y = Z?
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